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5120115543133 is a prime number
BaseRepresentation
bin100101010000001111010…
…1010110000110001011101
3200010110220122200221021221
41022200132222300301131
51132341444034340013
614520052033253341
71035626144014033
oct112403652606135
920113818627257
105120115543133
1116a4479819978
126a8390404251
132b1a951a4a46
14139b5a1a8553
158d2bc8ec08d
hex4a81eab0c5d

5120115543133 has 2 divisors, whose sum is σ = 5120115543134. Its totient is φ = 5120115543132.

The previous prime is 5120115543083. The next prime is 5120115543157. The reversal of 5120115543133 is 3313455110215.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 4131389586724 + 988725956409 = 2032582^2 + 994347^2 .

It is a cyclic number.

It is not a de Polignac number, because 5120115543133 - 237 = 4982676589661 is a prime.

It is a super-3 number, since 3×51201155431333 (a number of 39 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5120115543163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560057771566 + 2560057771567.

It is an arithmetic number, because the mean of its divisors is an integer number (2560057771567).

Almost surely, 25120115543133 is an apocalyptic number.

It is an amenable number.

5120115543133 is a deficient number, since it is larger than the sum of its proper divisors (1).

5120115543133 is an equidigital number, since it uses as much as digits as its factorization.

5120115543133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27000, while the sum is 34.

The spelling of 5120115543133 in words is "five trillion, one hundred twenty billion, one hundred fifteen million, five hundred forty-three thousand, one hundred thirty-three".