Base | Representation |
---|---|
bin | 101111101011110101… |
… | …101001111001111101 |
3 | 11220011022101010210012 |
4 | 233223311221321331 |
5 | 1314330021220133 |
6 | 35304354353005 |
7 | 3461550206441 |
oct | 575365517175 |
9 | 156138333705 |
10 | 51201351293 |
11 | 1a794912064 |
12 | 9b0b28b765 |
13 | 4a9c918291 |
14 | 269a0d2821 |
15 | 14ea09ab48 |
hex | bebd69e7d |
51201351293 has 2 divisors, whose sum is σ = 51201351294. Its totient is φ = 51201351292.
The previous prime is 51201351287. The next prime is 51201351371. The reversal of 51201351293 is 39215310215.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 33409259524 + 17792091769 = 182782^2 + 133387^2 .
It is a cyclic number.
It is not a de Polignac number, because 51201351293 - 24 = 51201351277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51201350293) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25600675646 + 25600675647.
It is an arithmetic number, because the mean of its divisors is an integer number (25600675647).
Almost surely, 251201351293 is an apocalyptic number.
It is an amenable number.
51201351293 is a deficient number, since it is larger than the sum of its proper divisors (1).
51201351293 is an equidigital number, since it uses as much as digits as its factorization.
51201351293 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8100, while the sum is 32.
The spelling of 51201351293 in words is "fifty-one billion, two hundred one million, three hundred fifty-one thousand, two hundred ninety-three".
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