Base | Representation |
---|---|
bin | 10111010010001010000101… |
… | …01100001110001101010010 |
3 | 20201021210211021102022100211 |
4 | 23221011002230032031102 |
5 | 23202341004022240102 |
6 | 300521335351434334 |
7 | 13533116006216611 |
oct | 1351050254161522 |
9 | 221253737368324 |
10 | 51201424024402 |
11 | 15350447052853 |
12 | 58ab2193859aa |
13 | 227537304b572 |
14 | c9023acd9878 |
15 | 5dbcee8887d7 |
hex | 2e9142b0e352 |
51201424024402 has 32 divisors (see below), whose sum is σ = 82370950401600. Its totient is φ = 23795340798528.
The previous prime is 51201424024397. The next prime is 51201424024423. The reversal of 51201424024402 is 20442042410215.
It is a super-3 number, since 3×512014240244023 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 174324073 + ... + 174617539.
It is an arithmetic number, because the mean of its divisors is an integer number (2574092200050).
Almost surely, 251201424024402 is an apocalyptic number.
51201424024402 is a deficient number, since it is larger than the sum of its proper divisors (31169526377198).
51201424024402 is a wasteful number, since it uses less digits than its factorization.
51201424024402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 380170.
The product of its (nonzero) digits is 20480, while the sum is 31.
Adding to 51201424024402 its reverse (20442042410215), we get a palindrome (71643466434617).
The spelling of 51201424024402 in words is "fifty-one trillion, two hundred one billion, four hundred twenty-four million, twenty-four thousand, four hundred two".
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