Base | Representation |
---|---|
bin | 1110111001101110111… |
… | …00110011000010111101 |
3 | 1210221122100102101002021 |
4 | 13130313130303002331 |
5 | 31342120014413341 |
6 | 1031120214000141 |
7 | 51664421060521 |
oct | 7346734630275 |
9 | 1727570371067 |
10 | 512031404221 |
11 | 188173419577 |
12 | 8329a346051 |
13 | 3939095977c |
14 | 1aad5097d81 |
15 | d4bc0089d1 |
hex | 77377330bd |
512031404221 has 2 divisors, whose sum is σ = 512031404222. Its totient is φ = 512031404220.
The previous prime is 512031404207. The next prime is 512031404233. The reversal of 512031404221 is 122404130215.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 410098071321 + 101933332900 = 640389^2 + 319270^2 .
It is a cyclic number.
It is not a de Polignac number, because 512031404221 - 213 = 512031396029 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (512031404281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256015702110 + 256015702111.
It is an arithmetic number, because the mean of its divisors is an integer number (256015702111).
Almost surely, 2512031404221 is an apocalyptic number.
It is an amenable number.
512031404221 is a deficient number, since it is larger than the sum of its proper divisors (1).
512031404221 is an equidigital number, since it uses as much as digits as its factorization.
512031404221 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1920, while the sum is 25.
Adding to 512031404221 its reverse (122404130215), we get a palindrome (634435534436).
The spelling of 512031404221 in words is "five hundred twelve billion, thirty-one million, four hundred four thousand, two hundred twenty-one".
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