Base | Representation |
---|---|
bin | 100101010000101001101… |
… | …1101011110100101110111 |
3 | 200010120012101022200010221 |
4 | 1022201103131132211313 |
5 | 1132400302310100424 |
6 | 14520315553155211 |
7 | 1035660120305164 |
oct | 112412335364567 |
9 | 20116171280127 |
10 | 5121001253239 |
11 | 16a4893780aa3 |
12 | 6a8598b5bb07 |
13 | 2b1ba6837071 |
14 | 139c01a8506b |
15 | 8d3205549e4 |
hex | 4a85375e977 |
5121001253239 has 2 divisors, whose sum is σ = 5121001253240. Its totient is φ = 5121001253238.
The previous prime is 5121001253233. The next prime is 5121001253257. The reversal of 5121001253239 is 9323521001215.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5121001253239 - 219 = 5121000728951 is a prime.
It is a super-3 number, since 3×51210012532393 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5121001253233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560500626619 + 2560500626620.
It is an arithmetic number, because the mean of its divisors is an integer number (2560500626620).
Almost surely, 25121001253239 is an apocalyptic number.
5121001253239 is a deficient number, since it is larger than the sum of its proper divisors (1).
5121001253239 is an equidigital number, since it uses as much as digits as its factorization.
5121001253239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16200, while the sum is 34.
The spelling of 5121001253239 in words is "five trillion, one hundred twenty-one billion, one million, two hundred fifty-three thousand, two hundred thirty-nine".
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