Base | Representation |
---|---|
bin | 1001100010011110… |
… | …01110110101011001 |
3 | 111012220010222102221 |
4 | 10301033032311121 |
5 | 40441441400201 |
6 | 2204053424041 |
7 | 240622103566 |
oct | 46117166531 |
9 | 14186128387 |
10 | 5121043801 |
11 | 2198772005 |
12 | bab03b021 |
13 | 637c5c943 |
14 | 3681ad86d |
15 | 1ee8b64a1 |
hex | 1313ced59 |
5121043801 has 2 divisors, whose sum is σ = 5121043802. Its totient is φ = 5121043800.
The previous prime is 5121043783. The next prime is 5121043819. The reversal of 5121043801 is 1083401215.
It is a balanced prime because it is at equal distance from previous prime (5121043783) and next prime (5121043819).
It can be written as a sum of positive squares in only one way, i.e., 3392480025 + 1728563776 = 58245^2 + 41576^2 .
It is a cyclic number.
It is not a de Polignac number, because 5121043801 - 25 = 5121043769 is a prime.
It is a super-2 number, since 2×51210438012 = 52450179223521055202, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5121013801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560521900 + 2560521901.
It is an arithmetic number, because the mean of its divisors is an integer number (2560521901).
Almost surely, 25121043801 is an apocalyptic number.
It is an amenable number.
5121043801 is a deficient number, since it is larger than the sum of its proper divisors (1).
5121043801 is an equidigital number, since it uses as much as digits as its factorization.
5121043801 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 25.
The square root of 5121043801 is about 71561.4686895120. The cubic root of 5121043801 is about 1723.6648691235.
The spelling of 5121043801 in words is "five billion, one hundred twenty-one million, forty-three thousand, eight hundred one".
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