Base | Representation |
---|---|
bin | 100101010000110011101… |
… | …1000001000001101001110 |
3 | 200010121001200001211200021 |
4 | 1022201213120020031032 |
5 | 1132401443330121100 |
6 | 14520413051052354 |
7 | 1036001315413642 |
oct | 112414730101516 |
9 | 20117050054607 |
10 | 5121335395150 |
11 | 16a4a45354837 |
12 | 6a8670a410ba |
13 | 2b1c2ab2a180 |
14 | 139c341c4c22 |
15 | 8d33ea59a1a |
hex | 4a86760834e |
5121335395150 has 48 divisors (see below), whose sum is σ = 10282796108928. Its totient is φ = 1886462928000.
The previous prime is 5121335395129. The next prime is 5121335395151. The reversal of 5121335395150 is 515935331215.
It is a junction number, because it is equal to n+sod(n) for n = 5121335395097 and 5121335395106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5121335395151) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 9083806 + ... + 9631105.
It is an arithmetic number, because the mean of its divisors is an integer number (214224918936).
Almost surely, 25121335395150 is an apocalyptic number.
5121335395150 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
5121335395150 is an abundant number, since it is smaller than the sum of its proper divisors (5161460713778).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5121335395150 is a wasteful number, since it uses less digits than its factorization.
5121335395150 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18715357 (or 18715352 counting only the distinct ones).
The product of its (nonzero) digits is 303750, while the sum is 43.
The spelling of 5121335395150 in words is "five trillion, one hundred twenty-one billion, three hundred thirty-five million, three hundred ninety-five thousand, one hundred fifty".
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