Base | Representation |
---|---|
bin | 1110111010000011010… |
… | …11111010111101010011 |
3 | 1210222002022120111120202 |
4 | 13131001223322331103 |
5 | 31342443001002242 |
6 | 1031145230525415 |
7 | 52001604601631 |
oct | 7350153727523 |
9 | 1728068514522 |
10 | 512203140947 |
11 | 188251357953 |
12 | 8332796686b |
13 | 393ba3c9434 |
14 | 1ab0dc00351 |
15 | d4cc12d932 |
hex | 7741afaf53 |
512203140947 has 2 divisors, whose sum is σ = 512203140948. Its totient is φ = 512203140946.
The previous prime is 512203140929. The next prime is 512203140949. The reversal of 512203140947 is 749041302215.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-512203140947 is a prime.
Together with 512203140949, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 512203140947.
It is not a weakly prime, because it can be changed into another prime (512203140949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256101570473 + 256101570474.
It is an arithmetic number, because the mean of its divisors is an integer number (256101570474).
Almost surely, 2512203140947 is an apocalyptic number.
512203140947 is a deficient number, since it is larger than the sum of its proper divisors (1).
512203140947 is an equidigital number, since it uses as much as digits as its factorization.
512203140947 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 60480, while the sum is 38.
The spelling of 512203140947 in words is "five hundred twelve billion, two hundred three million, one hundred forty thousand, nine hundred forty-seven".
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