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5122140349853 is a prime number
BaseRepresentation
bin100101010001001011101…
…0110110010010110011101
3200010200010202201202221102
41022202113112302112131
51132410120412143403
614521025004042445
71036030261414442
oct112422726622635
920120122652842
105122140349853
1116a531876a15a
126a8856533425
132b2028826327
14139cad07d9c9
158d38a55eb88
hex4a8975b259d

5122140349853 has 2 divisors, whose sum is σ = 5122140349854. Its totient is φ = 5122140349852.

The previous prime is 5122140349829. The next prime is 5122140349873. The reversal of 5122140349853 is 3589430412215.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3889245461689 + 1232894888164 = 1972117^2 + 1110358^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5122140349853 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5122140349798 and 5122140349807.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5122140349873) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2561070174926 + 2561070174927.

It is an arithmetic number, because the mean of its divisors is an integer number (2561070174927).

Almost surely, 25122140349853 is an apocalyptic number.

It is an amenable number.

5122140349853 is a deficient number, since it is larger than the sum of its proper divisors (1).

5122140349853 is an equidigital number, since it uses as much as digits as its factorization.

5122140349853 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1036800, while the sum is 47.

The spelling of 5122140349853 in words is "five trillion, one hundred twenty-two billion, one hundred forty million, three hundred forty-nine thousand, eight hundred fifty-three".