Base | Representation |
---|---|
bin | 101111101101100100… |
… | …110101011010110101 |
3 | 11220020100012212101222 |
4 | 233231210311122311 |
5 | 1314410001341222 |
6 | 35311315200125 |
7 | 3462353014631 |
oct | 575544653265 |
9 | 156210185358 |
10 | 51230496437 |
11 | 1a7aa30925a |
12 | 9b18ba6045 |
13 | 4aa5981123 |
14 | 269dd1bdc1 |
15 | 14ec906542 |
hex | bed9356b5 |
51230496437 has 2 divisors, whose sum is σ = 51230496438. Its totient is φ = 51230496436.
The previous prime is 51230496433. The next prime is 51230496439. The reversal of 51230496437 is 73469403215.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47541877681 + 3688618756 = 218041^2 + 60734^2 .
It is a cyclic number.
It is not a de Polignac number, because 51230496437 - 22 = 51230496433 is a prime.
Together with 51230496439, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51230496431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25615248218 + 25615248219.
It is an arithmetic number, because the mean of its divisors is an integer number (25615248219).
Almost surely, 251230496437 is an apocalyptic number.
It is an amenable number.
51230496437 is a deficient number, since it is larger than the sum of its proper divisors (1).
51230496437 is an equidigital number, since it uses as much as digits as its factorization.
51230496437 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 544320, while the sum is 44.
The spelling of 51230496437 in words is "fifty-one billion, two hundred thirty million, four hundred ninety-six thousand, four hundred thirty-seven".
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