Base | Representation |
---|---|
bin | 10111010011000001111100… |
… | …01101001100000011000100 |
3 | 20201101200020022000010100021 |
4 | 23221200332031030003010 |
5 | 23203333413332120200 |
6 | 300543215251224524 |
7 | 13535230121045623 |
oct | 1351407615140304 |
9 | 221350208003307 |
10 | 51231413551300 |
11 | 15362136393224 |
12 | 58b4ba88a8144 |
13 | 22781421b7658 |
14 | c91883bb96ba |
15 | 5dc9a75e441a |
hex | 2e983e34c0c4 |
51231413551300 has 36 divisors (see below), whose sum is σ = 116005739907456. Its totient is φ = 19601584314400.
The previous prime is 51231413551267. The next prime is 51231413551391. The reversal of 51231413551300 is 315531413215.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 11137261516 + ... + 11137266115.
It is an arithmetic number, because the mean of its divisors is an integer number (3222381664096).
Almost surely, 251231413551300 is an apocalyptic number.
51231413551300 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
51231413551300 is an abundant number, since it is smaller than the sum of its proper divisors (64774326356156).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51231413551300 is a wasteful number, since it uses less digits than its factorization.
51231413551300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22274527668 (or 22274527661 counting only the distinct ones).
The product of its (nonzero) digits is 27000, while the sum is 34.
Adding to 51231413551300 its reverse (315531413215), we get a palindrome (51546944964515).
The spelling of 51231413551300 in words is "fifty-one trillion, two hundred thirty-one billion, four hundred thirteen million, five hundred fifty-one thousand, three hundred".
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