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51291729497 is a prime number
BaseRepresentation
bin101111110001001110…
…011010111001011001
311220101121102211101002
4233301032122321121
51320021140320442
635321343434345
73464025335651
oct576116327131
9156347384332
1051291729497
111a830931598
129b355b59b5
134ab55703c8
1426a80db361
151502e9e732
hexbf139ae59

51291729497 has 2 divisors, whose sum is σ = 51291729498. Its totient is φ = 51291729496.

The previous prime is 51291729479. The next prime is 51291729499. The reversal of 51291729497 is 79492719215.

It is a happy number.

Together with previous prime (51291729479) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 44914748761 + 6376980736 = 211931^2 + 79856^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51291729497 is a prime.

Together with 51291729499, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (51291729499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25645864748 + 25645864749.

It is an arithmetic number, because the mean of its divisors is an integer number (25645864749).

Almost surely, 251291729497 is an apocalyptic number.

It is an amenable number.

51291729497 is a deficient number, since it is larger than the sum of its proper divisors (1).

51291729497 is an equidigital number, since it uses as much as digits as its factorization.

51291729497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2857680, while the sum is 56.

The spelling of 51291729497 in words is "fifty-one billion, two hundred ninety-one million, seven hundred twenty-nine thousand, four hundred ninety-seven".