513000000181 has 2 divisors, whose sum is σ = 513000000182. Its totient is φ = 513000000180.

The previous prime is 513000000103. The next prime is 513000000197. The reversal of 513000000181 is 181000000315.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 503681187025 + 9318813156 = 709705^2 + 96534^2 .

It is a cyclic number.

It is not a de Polignac number, because 513000000181 - 2¹⁵ = 512999967413 is a prime.

It is a super-2 number, since 2×513000000181² (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (513000000581) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256500000090 + 256500000091.

It is an arithmetic number, because the mean of its divisors is an integer number (256500000091).

Almost surely, 2^513000000181 is an apocalyptic number.

It is an amenable number.

513000000181 is a deficient number, since it is larger than the sum of its proper divisors (1).

513000000181 is an equidigital number, since it uses as much as digits as its factorization.

513000000181 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 120, while the sum is 19.

Adding to 513000000181 its reverse (181000000315), we get a palindrome (694000000496).

The spelling of 513000000181 in words is "five hundred thirteen billion, one hundred eighty-one", and thus it is an aban number.