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513000000197 is a prime number
BaseRepresentation
bin1110111011100010010…
…11101100101011000101
31211001010212000010222022
413131301023230223011
531401111000001242
61031400254212525
752030422024506
oct7356113545305
91731125003868
10513000000197
11188620143013
128350a7b4145
13394b651c899
141ab8798cbad
15d5270850d2
hex77712ecac5

513000000197 has 2 divisors, whose sum is σ = 513000000198. Its totient is φ = 513000000196.

The previous prime is 513000000181. The next prime is 513000000259. The reversal of 513000000197 is 791000000315.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 334082844001 + 178917156196 = 577999^2 + 422986^2 .

It is a cyclic number.

It is not a de Polignac number, because 513000000197 - 24 = 513000000181 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (513000000797) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256500000098 + 256500000099.

It is an arithmetic number, because the mean of its divisors is an integer number (256500000099).

Almost surely, 2513000000197 is an apocalyptic number.

It is an amenable number.

513000000197 is a deficient number, since it is larger than the sum of its proper divisors (1).

513000000197 is an equidigital number, since it uses as much as digits as its factorization.

513000000197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 945, while the sum is 26.

The spelling of 513000000197 in words is "five hundred thirteen billion, one hundred ninety-seven", and thus it is an aban number.