Base | Representation |
---|---|
bin | 1001100011100010… |
… | …11100011010011111 |
3 | 111020112000121221021 |
4 | 10301301130122133 |
5 | 41001240343234 |
6 | 2205013545011 |
7 | 241061246065 |
oct | 46161343237 |
9 | 14215017837 |
10 | 5130012319 |
11 | 21a2838203 |
12 | bb2045167 |
13 | 639a7cb63 |
14 | 369466035 |
15 | 2005889b4 |
hex | 131c5c69f |
5130012319 has 2 divisors, whose sum is σ = 5130012320. Its totient is φ = 5130012318.
The previous prime is 5130012313. The next prime is 5130012323. The reversal of 5130012319 is 9132100315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5130012319 - 25 = 5130012287 is a prime.
It is a super-2 number, since 2×51300123192 = 52634052786183515522, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5130012293 and 5130012302.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5130012313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2565006159 + 2565006160.
It is an arithmetic number, because the mean of its divisors is an integer number (2565006160).
Almost surely, 25130012319 is an apocalyptic number.
5130012319 is a deficient number, since it is larger than the sum of its proper divisors (1).
5130012319 is an equidigital number, since it uses as much as digits as its factorization.
5130012319 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810, while the sum is 25.
The square root of 5130012319 is about 71624.1043155166. The cubic root of 5130012319 is about 1724.6705042021.
The spelling of 5130012319 in words is "five billion, one hundred thirty million, twelve thousand, three hundred nineteen".
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