Base | Representation |
---|---|
bin | 1110111011100110001… |
… | …10010000111111001111 |
3 | 1211001020002110112110221 |
4 | 13131303012100333033 |
5 | 31401142211134021 |
6 | 1031403403012211 |
7 | 52031262105055 |
oct | 7356306207717 |
9 | 1731202415427 |
10 | 513032130511 |
11 | 188637298a9a |
12 | 8351950a067 |
13 | 394c008c3c4 |
14 | 1ab8bd541d5 |
15 | d529cd0241 |
hex | 7773190fcf |
513032130511 has 2 divisors, whose sum is σ = 513032130512. Its totient is φ = 513032130510.
The previous prime is 513032130433. The next prime is 513032130517. The reversal of 513032130511 is 115031230315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 513032130511 - 227 = 512897912783 is a prime.
It is a super-2 number, since 2×5130321305112 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (513032130517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256516065255 + 256516065256.
It is an arithmetic number, because the mean of its divisors is an integer number (256516065256).
Almost surely, 2513032130511 is an apocalyptic number.
513032130511 is a deficient number, since it is larger than the sum of its proper divisors (1).
513032130511 is an equidigital number, since it uses as much as digits as its factorization.
513032130511 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1350, while the sum is 25.
Adding to 513032130511 its reverse (115031230315), we get a palindrome (628063360826).
The spelling of 513032130511 in words is "five hundred thirteen billion, thirty-two million, one hundred thirty thousand, five hundred eleven".
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