Base | Representation |
---|---|
bin | 1110111011101111100… |
… | …11010101010010001101 |
3 | 1211001102120222020101212 |
4 | 13131313303111102031 |
5 | 31401322412202303 |
6 | 1031415302344205 |
7 | 52033240664105 |
oct | 7356763252215 |
9 | 1731376866355 |
10 | 513111053453 |
11 | 1886778a3a69 |
12 | 8353ba2b065 |
13 | 3950353347b |
14 | 1ab9861a205 |
15 | d531bbead8 |
hex | 7777cd548d |
513111053453 has 2 divisors, whose sum is σ = 513111053454. Its totient is φ = 513111053452.
The previous prime is 513111053401. The next prime is 513111053491. The reversal of 513111053453 is 354350111315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 437770136164 + 75340917289 = 661642^2 + 274483^2 .
It is a cyclic number.
It is not a de Polignac number, because 513111053453 - 210 = 513111052429 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (513111013453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256555526726 + 256555526727.
It is an arithmetic number, because the mean of its divisors is an integer number (256555526727).
Almost surely, 2513111053453 is an apocalyptic number.
It is an amenable number.
513111053453 is a deficient number, since it is larger than the sum of its proper divisors (1).
513111053453 is an equidigital number, since it uses as much as digits as its factorization.
513111053453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13500, while the sum is 32.
Adding to 513111053453 its reverse (354350111315), we get a palindrome (867461164768).
The spelling of 513111053453 in words is "five hundred thirteen billion, one hundred eleven million, fifty-three thousand, four hundred fifty-three".
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