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51311207 is a prime number
BaseRepresentation
bin1100001110111…
…1001001100111
310120112212202002
43003233021213
5101113424312
65031435515
71162065233
oct303571147
9116485662
1051311207
1126a66962
1215225b9b
13a82717c
146b595c3
1547884c2
hex30ef267

51311207 has 2 divisors, whose sum is σ = 51311208. Its totient is φ = 51311206.

The previous prime is 51311171. The next prime is 51311209. The reversal of 51311207 is 70211315.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 51311207 - 28 = 51310951 is a prime.

Together with 51311209, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51311209) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25655603 + 25655604.

It is an arithmetic number, because the mean of its divisors is an integer number (25655604).

Almost surely, 251311207 is an apocalyptic number.

51311207 is a deficient number, since it is larger than the sum of its proper divisors (1).

51311207 is an equidigital number, since it uses as much as digits as its factorization.

51311207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 210, while the sum is 20.

The square root of 51311207 is about 7163.1841383563. The cubic root of 51311207 is about 371.5957545564.

The spelling of 51311207 in words is "fifty-one million, three hundred eleven thousand, two hundred seven".