Base | Representation |
---|---|
bin | 111010010110111110111111… |
… | …0110001000011101100111111 |
3 | 2111022120002110012111202201002 |
4 | 1310231331332301003230333 |
5 | 1014240414044144240223 |
6 | 5015433340314240515 |
7 | 213061015335112232 |
oct | 16455757661035477 |
9 | 2438502405452632 |
10 | 513332323040063 |
11 | 1396220198a020a |
12 | 496a72b042613b |
13 | 190580518c3cc7 |
14 | 90a95ba377419 |
15 | 3e52e42290e28 |
hex | 1d2df7ec43b3f |
513332323040063 has 2 divisors, whose sum is σ = 513332323040064. Its totient is φ = 513332323040062.
The previous prime is 513332323040059. The next prime is 513332323040177. The reversal of 513332323040063 is 360040323233315.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 513332323040063 - 22 = 513332323040059 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 513332323039999 and 513332323040026.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (513332323040263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256666161520031 + 256666161520032.
It is an arithmetic number, because the mean of its divisors is an integer number (256666161520032).
Almost surely, 2513332323040063 is an apocalyptic number.
513332323040063 is a deficient number, since it is larger than the sum of its proper divisors (1).
513332323040063 is an equidigital number, since it uses as much as digits as its factorization.
513332323040063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 349920, while the sum is 38.
Adding to 513332323040063 its reverse (360040323233315), we get a palindrome (873372646273378).
The spelling of 513332323040063 in words is "five hundred thirteen trillion, three hundred thirty-two billion, three hundred twenty-three million, forty thousand, sixty-three".
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