Base | Representation |
---|---|
bin | 100101010110100010111… |
… | …1000010110000111110101 |
3 | 200011202212110211010221101 |
4 | 1022231011320112013311 |
5 | 1133102213012123201 |
6 | 14530211534050101 |
7 | 1036615560466453 |
oct | 112550570260765 |
9 | 20152773733841 |
10 | 5133658317301 |
11 | 16aa199316618 |
12 | 6aab2b949931 |
13 | 2b3142b56c97 |
14 | 13a682a619d3 |
15 | 8d811815d01 |
hex | 4ab45e161f5 |
5133658317301 has 2 divisors, whose sum is σ = 5133658317302. Its totient is φ = 5133658317300.
The previous prime is 5133658317233. The next prime is 5133658317317. The reversal of 5133658317301 is 1037138563315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3593018816676 + 1540639500625 = 1895526^2 + 1241225^2 .
It is a cyclic number.
It is not a de Polignac number, because 5133658317301 - 27 = 5133658317173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5133658317401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2566829158650 + 2566829158651.
It is an arithmetic number, because the mean of its divisors is an integer number (2566829158651).
Almost surely, 25133658317301 is an apocalyptic number.
It is an amenable number.
5133658317301 is a deficient number, since it is larger than the sum of its proper divisors (1).
5133658317301 is an equidigital number, since it uses as much as digits as its factorization.
5133658317301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 680400, while the sum is 46.
The spelling of 5133658317301 in words is "five trillion, one hundred thirty-three billion, six hundred fifty-eight million, three hundred seventeen thousand, three hundred one".
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