Base | Representation |
---|---|
bin | 100101010110100010111… |
… | …1000010110001000000101 |
3 | 200011202212110211010221222 |
4 | 1022231011320112020011 |
5 | 1133102213012123232 |
6 | 14530211534050125 |
7 | 1036615560466505 |
oct | 112550570261005 |
9 | 20152773733858 |
10 | 5133658317317 |
11 | 16aa199316632 |
12 | 6aab2b949945 |
13 | 2b3142b56caa |
14 | 13a682a61a05 |
15 | 8d811815d12 |
hex | 4ab45e16205 |
5133658317317 has 2 divisors, whose sum is σ = 5133658317318. Its totient is φ = 5133658317316.
The previous prime is 5133658317301. The next prime is 5133658317343. The reversal of 5133658317317 is 7137138563315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4746955920001 + 386702397316 = 2178751^2 + 621854^2 .
It is a cyclic number.
It is not a de Polignac number, because 5133658317317 - 24 = 5133658317301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5133858317317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2566829158658 + 2566829158659.
It is an arithmetic number, because the mean of its divisors is an integer number (2566829158659).
Almost surely, 25133658317317 is an apocalyptic number.
It is an amenable number.
5133658317317 is a deficient number, since it is larger than the sum of its proper divisors (1).
5133658317317 is an equidigital number, since it uses as much as digits as its factorization.
5133658317317 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4762800, while the sum is 53.
The spelling of 5133658317317 in words is "five trillion, one hundred thirty-three billion, six hundred fifty-eight million, three hundred seventeen thousand, three hundred seventeen".
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