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51342554420981 is a prime number
BaseRepresentation
bin10111010110010000111101…
…01101111101011011110101
320201210022002220011021200222
423223020132231331123311
523212144022412432411
6301110235513544125
713546243234622015
oct1353103655753365
9221708086137628
1051342554420981
11153a528952263a
125912645715045
132285774b74875
14c96dc86d9c45
155e080e9474db
hex2eb21eb7d6f5

51342554420981 has 2 divisors, whose sum is σ = 51342554420982. Its totient is φ = 51342554420980.

The previous prime is 51342554420977. The next prime is 51342554421061. The reversal of 51342554420981 is 18902445524315.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 50585750117956 + 756804303025 = 7112366^2 + 869945^2 .

It is a cyclic number.

It is not a de Polignac number, because 51342554420981 - 22 = 51342554420977 is a prime.

It is a super-2 number, since 2×513425544209812 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51342554420281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25671277210490 + 25671277210491.

It is an arithmetic number, because the mean of its divisors is an integer number (25671277210491).

Almost surely, 251342554420981 is an apocalyptic number.

It is an amenable number.

51342554420981 is a deficient number, since it is larger than the sum of its proper divisors (1).

51342554420981 is an equidigital number, since it uses as much as digits as its factorization.

51342554420981 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6912000, while the sum is 53.

The spelling of 51342554420981 in words is "fifty-one trillion, three hundred forty-two billion, five hundred fifty-four million, four hundred twenty thousand, nine hundred eighty-one".