Base | Representation |
---|---|
bin | 1110111100010111000… |
… | …11000100001101100101 |
3 | 1211002021200100000020202 |
4 | 13132023203010031211 |
5 | 31403012214133131 |
6 | 1031512215040245 |
7 | 52044402553214 |
oct | 7361343041545 |
9 | 1732250300222 |
10 | 513442333541 |
11 | 1888278a2665 |
12 | 83612970085 |
13 | 39557063aa7 |
14 | 1abca61307b |
15 | d550d0bbcb |
hex | 778b8c4365 |
513442333541 has 2 divisors, whose sum is σ = 513442333542. Its totient is φ = 513442333540.
The previous prime is 513442333531. The next prime is 513442333549. The reversal of 513442333541 is 145333244315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 454708811041 + 58733522500 = 674321^2 + 242350^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-513442333541 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 513442333495 and 513442333504.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (513442333549) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256721166770 + 256721166771.
It is an arithmetic number, because the mean of its divisors is an integer number (256721166771).
Almost surely, 2513442333541 is an apocalyptic number.
It is an amenable number.
513442333541 is a deficient number, since it is larger than the sum of its proper divisors (1).
513442333541 is an equidigital number, since it uses as much as digits as its factorization.
513442333541 is an evil number, because the sum of its binary digits is even.
The product of its digits is 259200, while the sum is 38.
Adding to 513442333541 its reverse (145333244315), we get a palindrome (658775577856).
The spelling of 513442333541 in words is "five hundred thirteen billion, four hundred forty-two million, three hundred thirty-three thousand, five hundred forty-one".
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