Base | Representation |
---|---|
bin | 10111010110010101101000… |
… | …00101101000100110100101 |
3 | 20201210112120112122211221202 |
4 | 23223022310011220212211 |
5 | 23212214140432313133 |
6 | 301111332314252245 |
7 | 13546362314435315 |
oct | 1353126405504645 |
9 | 221715515584852 |
10 | 51345060432293 |
11 | 153a6355061a71 |
12 | 5913024a27085 |
13 | 2285a840ca1b4 |
14 | c97185473445 |
15 | 5e090995e2e8 |
hex | 2eb2b41689a5 |
51345060432293 has 2 divisors, whose sum is σ = 51345060432294. Its totient is φ = 51345060432292.
The previous prime is 51345060432227. The next prime is 51345060432317. The reversal of 51345060432293 is 39223406054315.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 35614135546564 + 15730924885729 = 5967758^2 + 3966223^2 .
It is a cyclic number.
It is not a de Polignac number, because 51345060432293 - 218 = 51345060170149 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51345060432223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25672530216146 + 25672530216147.
It is an arithmetic number, because the mean of its divisors is an integer number (25672530216147).
Almost surely, 251345060432293 is an apocalyptic number.
It is an amenable number.
51345060432293 is a deficient number, since it is larger than the sum of its proper divisors (1).
51345060432293 is an equidigital number, since it uses as much as digits as its factorization.
51345060432293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2332800, while the sum is 47.
The spelling of 51345060432293 in words is "fifty-one trillion, three hundred forty-five billion, sixty million, four hundred thirty-two thousand, two hundred ninety-three".
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