Base | Representation |
---|---|
bin | 101111110100101111… |
… | …001111111101111101 |
3 | 11220112201100011121111 |
4 | 233310233033331331 |
5 | 1320131232322013 |
6 | 35331251002021 |
7 | 3465342316543 |
oct | 576457177575 |
9 | 156481304544 |
10 | 51350667133 |
11 | 1a861127287 |
12 | 9b51299311 |
13 | 4ac483794c |
14 | 26b1c7dd93 |
15 | 150824273d |
hex | bf4bcff7d |
51350667133 has 2 divisors, whose sum is σ = 51350667134. Its totient is φ = 51350667132.
The previous prime is 51350667131. The next prime is 51350667149. The reversal of 51350667133 is 33176605315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 43308523449 + 8042143684 = 208107^2 + 89678^2 .
It is a cyclic number.
It is not a de Polignac number, because 51350667133 - 21 = 51350667131 is a prime.
Together with 51350667131, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51350667131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25675333566 + 25675333567.
It is an arithmetic number, because the mean of its divisors is an integer number (25675333567).
Almost surely, 251350667133 is an apocalyptic number.
It is an amenable number.
51350667133 is a deficient number, since it is larger than the sum of its proper divisors (1).
51350667133 is an equidigital number, since it uses as much as digits as its factorization.
51350667133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 170100, while the sum is 40.
The spelling of 51350667133 in words is "fifty-one billion, three hundred fifty million, six hundred sixty-seven thousand, one hundred thirty-three".
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