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513512355025493 is a prime number
BaseRepresentation
bin111010011000010010110100…
…1100000100101001001010101
32111100012022010221110012201022
41310300211221200211021111
51014301341300341303433
65020052152540410525
7213110020602540305
oct16460455140451125
92440168127405638
10513512355025493
1113969140419952a
1249716174846a45
131906c013057135
1490b41b84db605
153e5797c6b6698
hex1d30969825255

513512355025493 has 2 divisors, whose sum is σ = 513512355025494. Its totient is φ = 513512355025492.

The previous prime is 513512355025441. The next prime is 513512355025531. The reversal of 513512355025493 is 394520553215315.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 388452485803204 + 125059869222289 = 19709198^2 + 11183017^2 .

It is a cyclic number.

It is not a de Polignac number, because 513512355025493 - 26 = 513512355025429 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (513512352025493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256756177512746 + 256756177512747.

It is an arithmetic number, because the mean of its divisors is an integer number (256756177512747).

Almost surely, 2513512355025493 is an apocalyptic number.

It is an amenable number.

513512355025493 is a deficient number, since it is larger than the sum of its proper divisors (1).

513512355025493 is an equidigital number, since it uses as much as digits as its factorization.

513512355025493 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12150000, while the sum is 53.

The spelling of 513512355025493 in words is "five hundred thirteen trillion, five hundred twelve billion, three hundred fifty-five million, twenty-five thousand, four hundred ninety-three".