Base | Representation |
---|---|
bin | 10111010110101000101101… |
… | …10011010111100000000111 |
3 | 20201211112000121111011120002 |
4 | 23223110112303113200013 |
5 | 23212401131432211011 |
6 | 301120145131431515 |
7 | 13550204240656646 |
oct | 1353242663274007 |
9 | 221745017434502 |
10 | 51355306522631 |
11 | 153aa73277a321 |
12 | 59150042b559b |
13 | 2286a27a8b647 |
14 | c9787817535d |
15 | 5e0d0922cc3b |
hex | 2eb516cd7807 |
51355306522631 has 2 divisors, whose sum is σ = 51355306522632. Its totient is φ = 51355306522630.
The previous prime is 51355306522523. The next prime is 51355306522687. The reversal of 51355306522631 is 13622560355315.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51355306522631 - 234 = 51338126653447 is a prime.
It is a super-2 number, since 2×513553065226312 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51355302522631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25677653261315 + 25677653261316.
It is an arithmetic number, because the mean of its divisors is an integer number (25677653261316).
Almost surely, 251355306522631 is an apocalyptic number.
51355306522631 is a deficient number, since it is larger than the sum of its proper divisors (1).
51355306522631 is an equidigital number, since it uses as much as digits as its factorization.
51355306522631 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2430000, while the sum is 47.
Adding to 51355306522631 its reverse (13622560355315), we get a palindrome (64977866877946).
The spelling of 51355306522631 in words is "fifty-one trillion, three hundred fifty-five billion, three hundred six million, five hundred twenty-two thousand, six hundred thirty-one".
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