Base | Representation |
---|---|
bin | 100101010111011010110… |
… | …0111001111001010111011 |
3 | 200011221201010010211022122 |
4 | 1022232311213033022323 |
5 | 1133120032404134241 |
6 | 14531121540311455 |
7 | 1040013202144502 |
oct | 112566547171273 |
9 | 20157633124278 |
10 | 5135532880571 |
11 | 16aaa70478765 |
12 | 6ab3736a258b |
13 | 2b3381322912 |
14 | 13a7bd9c7839 |
15 | 8d8c119c04b |
hex | 4abb59cf2bb |
5135532880571 has 2 divisors, whose sum is σ = 5135532880572. Its totient is φ = 5135532880570.
The previous prime is 5135532880553. The next prime is 5135532880591. The reversal of 5135532880571 is 1750882355315.
It is a happy number.
5135532880571 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5135532880571 is a prime.
It is not a weakly prime, because it can be changed into another prime (5135532880591) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2567766440285 + 2567766440286.
It is an arithmetic number, because the mean of its divisors is an integer number (2567766440286).
Almost surely, 25135532880571 is an apocalyptic number.
5135532880571 is a deficient number, since it is larger than the sum of its proper divisors (1).
5135532880571 is an equidigital number, since it uses as much as digits as its factorization.
5135532880571 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040000, while the sum is 53.
The spelling of 5135532880571 in words is "five trillion, one hundred thirty-five billion, five hundred thirty-two million, eight hundred eighty thousand, five hundred seventy-one".
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