Base | Representation |
---|---|
bin | 10111010110111001101101… |
… | …10110011011110011101000 |
3 | 20201212101120201200202222202 |
4 | 23223130312312123303220 |
5 | 23213023330114212300 |
6 | 301124254552035332 |
7 | 13550646363244400 |
oct | 1353346666336350 |
9 | 221771521622882 |
10 | 51364434132200 |
11 | 15403596aaa502 |
12 | 5916931092b48 |
13 | 2287850acb357 |
14 | c980a24c7800 |
15 | 5e1190714ad5 |
hex | 2eb736d9bce8 |
51364434132200 has 72 divisors (see below), whose sum is σ = 138919829278950. Its totient is φ = 17610663127680.
The previous prime is 51364434132199. The next prime is 51364434132239. The reversal of 51364434132200 is 223143446315.
It can be written as a sum of positive squares in 3 ways, for example, as 32445988115044 + 18918446017156 = 5696138^2 + 4349534^2 .
It is a super-2 number, since 2×513644341322002 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 2620624595 + ... + 2620644194.
Almost surely, 251364434132200 is an apocalyptic number.
51364434132200 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
51364434132200 is an abundant number, since it is smaller than the sum of its proper divisors (87555395146750).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51364434132200 is a wasteful number, since it uses less digits than its factorization.
51364434132200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5241268819 (or 5241268803 counting only the distinct ones).
The product of its (nonzero) digits is 207360, while the sum is 38.
Adding to 51364434132200 its reverse (223143446315), we get a palindrome (51587577578515).
The spelling of 51364434132200 in words is "fifty-one trillion, three hundred sixty-four billion, four hundred thirty-four million, one hundred thirty-two thousand, two hundred".
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