Base | Representation |
---|---|
bin | 10111010111000000101111… |
… | …11100110001101001100101 |
3 | 20201212202022220220200100222 |
4 | 23223200113330301221211 |
5 | 23213104043412340013 |
6 | 301130121420214125 |
7 | 13551142101256262 |
oct | 1353402774615145 |
9 | 221782286820328 |
10 | 51368210668133 |
11 | 15405154834887 |
12 | 591760599a345 |
13 | 228800333b6b8 |
14 | c9833dcac269 |
15 | 5e1312048508 |
hex | 2eb817f31a65 |
51368210668133 has 2 divisors, whose sum is σ = 51368210668134. Its totient is φ = 51368210668132.
The previous prime is 51368210668063. The next prime is 51368210668267. The reversal of 51368210668133 is 33186601286315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 46415102256769 + 4953108411364 = 6812863^2 + 2225558^2 .
It is a cyclic number.
It is not a de Polignac number, because 51368210668133 - 236 = 51299491191397 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51368210667133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25684105334066 + 25684105334067.
It is an arithmetic number, because the mean of its divisors is an integer number (25684105334067).
Almost surely, 251368210668133 is an apocalyptic number.
It is an amenable number.
51368210668133 is a deficient number, since it is larger than the sum of its proper divisors (1).
51368210668133 is an equidigital number, since it uses as much as digits as its factorization.
51368210668133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3732480, while the sum is 53.
The spelling of 51368210668133 in words is "fifty-one trillion, three hundred sixty-eight billion, two hundred ten million, six hundred sixty-eight thousand, one hundred thirty-three".
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