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5138830215511 is a prime number
BaseRepresentation
bin100101011000111101000…
…1001100100100101010111
3200012021012220122210111221
41022301322021210211113
51133143311013344021
614532425045511211
71040161001060056
oct112617211444527
920167186583457
105138830215511
111701402762263
126abb33a12507
132b37884b0b95
1413aa138ac39d
158da158c5241
hex4ac7a264957

5138830215511 has 2 divisors, whose sum is σ = 5138830215512. Its totient is φ = 5138830215510.

The previous prime is 5138830215509. The next prime is 5138830215529. The reversal of 5138830215511 is 1155120388315.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5138830215511 - 21 = 5138830215509 is a prime.

It is a super-2 number, since 2×51388302155112 (a number of 26 digits) contains 22 as substring.

Together with 5138830215509, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5138830815511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2569415107755 + 2569415107756.

It is an arithmetic number, because the mean of its divisors is an integer number (2569415107756).

Almost surely, 25138830215511 is an apocalyptic number.

5138830215511 is a deficient number, since it is larger than the sum of its proper divisors (1).

5138830215511 is an equidigital number, since it uses as much as digits as its factorization.

5138830215511 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144000, while the sum is 43.

The spelling of 5138830215511 in words is "five trillion, one hundred thirty-eight billion, eight hundred thirty million, two hundred fifteen thousand, five hundred eleven".