Base | Representation |
---|---|
bin | 1001100100101011… |
… | …01000010001000101 |
3 | 111021011212112220202 |
4 | 10302111220101011 |
5 | 41011202414203 |
6 | 2205553140245 |
7 | 241235004224 |
oct | 46225502105 |
9 | 14234775822 |
10 | 5139498053 |
11 | 21a8126a58 |
12 | bb525a685 |
13 | 63ba21611 |
14 | 36a814cbb |
15 | 20130e388 |
hex | 132568445 |
5139498053 has 2 divisors, whose sum is σ = 5139498054. Its totient is φ = 5139498052.
The previous prime is 5139498047. The next prime is 5139498071. The reversal of 5139498053 is 3508949315.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5135585569 + 3912484 = 71663^2 + 1978^2 .
It is a cyclic number.
It is not a de Polignac number, because 5139498053 - 24 = 5139498037 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5139497989 and 5139498007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5139498853) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2569749026 + 2569749027.
It is an arithmetic number, because the mean of its divisors is an integer number (2569749027).
Almost surely, 25139498053 is an apocalyptic number.
It is an amenable number.
5139498053 is a deficient number, since it is larger than the sum of its proper divisors (1).
5139498053 is an equidigital number, since it uses as much as digits as its factorization.
5139498053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 583200, while the sum is 47.
The square root of 5139498053 is about 71690.2925994866. The cubic root of 5139498053 is about 1725.7328598417.
The spelling of 5139498053 in words is "five billion, one hundred thirty-nine million, four hundred ninety-eight thousand, fifty-three".
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