Base | Representation |
---|---|
bin | 111010011100111001001010… |
… | …0010000100010001101110111 |
3 | 2111102102201122111121100120001 |
4 | 1310321302110100202031313 |
5 | 1014342220244200310431 |
6 | 5021254405213052131 |
7 | 213203465222051014 |
oct | 16471622420421567 |
9 | 2442381574540501 |
10 | 514144432431991 |
11 | 13990547a432329 |
12 | 497b8776187047 |
13 | 190b67c558683a |
14 | 90d6a1aa7470b |
15 | 3e69123710e61 |
hex | 1d39c94422377 |
514144432431991 has 2 divisors, whose sum is σ = 514144432431992. Its totient is φ = 514144432431990.
The previous prime is 514144432431947. The next prime is 514144432432051. The reversal of 514144432431991 is 199134234441415.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 514144432431991 - 213 = 514144432423799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (514144432431941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257072216215995 + 257072216215996.
It is an arithmetic number, because the mean of its divisors is an integer number (257072216215996).
Almost surely, 2514144432431991 is an apocalyptic number.
514144432431991 is a deficient number, since it is larger than the sum of its proper divisors (1).
514144432431991 is an equidigital number, since it uses as much as digits as its factorization.
514144432431991 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7464960, while the sum is 55.
The spelling of 514144432431991 in words is "five hundred fourteen trillion, one hundred forty-four billion, four hundred thirty-two million, four hundred thirty-one thousand, nine hundred ninety-one".
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