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51431011230 = 2351714367041
BaseRepresentation
bin101111111001100001…
…101111001110011110
311220202022112001222210
4233321201233032132
51320312314324410
635343241021250
73500336245104
oct577141571636
9156668461883
1051431011230
111a8a2512a65
129b74184826
134b08388831
1426bc7d5c74
151510313220
hexbf986f39e

51431011230 has 16 divisors (see below), whose sum is σ = 123434427024. Its totient is φ = 13714936320.

The previous prime is 51431011223. The next prime is 51431011253. The reversal of 51431011230 is 3211013415.

It is a super-2 number, since 2×514310112302 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51431011197 and 51431011206.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 857183491 + ... + 857183550.

It is an arithmetic number, because the mean of its divisors is an integer number (7714651689).

Almost surely, 251431011230 is an apocalyptic number.

51431011230 is an abundant number, since it is smaller than the sum of its proper divisors (72003415794).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

51431011230 is a wasteful number, since it uses less digits than its factorization.

51431011230 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1714367051.

The product of its (nonzero) digits is 360, while the sum is 21.

Adding to 51431011230 its reverse (3211013415), we get a palindrome (54642024645).

The spelling of 51431011230 in words is "fifty-one billion, four hundred thirty-one million, eleven thousand, two hundred thirty".

Divisors: 1 2 3 5 6 10 15 30 1714367041 3428734082 5143101123 8571835205 10286202246 17143670410 25715505615 51431011230