Base | Representation |
---|---|
bin | 101111111001100011… |
… | …010110001110111101 |
3 | 11220202100022111202102 |
4 | 233321203112032331 |
5 | 1320312421330044 |
6 | 35343254034445 |
7 | 3500342653145 |
oct | 577143261675 |
9 | 156670274672 |
10 | 51431433149 |
11 | 1a8a2780a58 |
12 | 9b74348a25 |
13 | 4b084a58a5 |
14 | 26bc8a5925 |
15 | 151039824e |
hex | bf98d63bd |
51431433149 has 2 divisors, whose sum is σ = 51431433150. Its totient is φ = 51431433148.
The previous prime is 51431433101. The next prime is 51431433169. The reversal of 51431433149 is 94133413415.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 42933912025 + 8497521124 = 207205^2 + 92182^2 .
It is a cyclic number.
It is not a de Polignac number, because 51431433149 - 28 = 51431432893 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51431433169) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25715716574 + 25715716575.
It is an arithmetic number, because the mean of its divisors is an integer number (25715716575).
Almost surely, 251431433149 is an apocalyptic number.
It is an amenable number.
51431433149 is a deficient number, since it is larger than the sum of its proper divisors (1).
51431433149 is an equidigital number, since it uses as much as digits as its factorization.
51431433149 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 77760, while the sum is 38.
The spelling of 51431433149 in words is "fifty-one billion, four hundred thirty-one million, four hundred thirty-three thousand, one hundred forty-nine".
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