Base | Representation |
---|---|
bin | 101111111001101011… |
… | …000010101011101111 |
3 | 11220202111002222122212 |
4 | 233321223002223233 |
5 | 1320313430401343 |
6 | 35343405201035 |
7 | 3500366053631 |
oct | 577153025357 |
9 | 156674088585 |
10 | 51433450223 |
11 | 1a8a3929461 |
12 | 9b74b6017b |
13 | 4b08a30a1c |
14 | 26bcc6ca51 |
15 | 1510645c18 |
hex | bf9ac2aef |
51433450223 has 2 divisors, whose sum is σ = 51433450224. Its totient is φ = 51433450222.
The previous prime is 51433450171. The next prime is 51433450231. The reversal of 51433450223 is 32205433415.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51433450223 - 222 = 51429255919 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 51433450223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51433452223) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25716725111 + 25716725112.
It is an arithmetic number, because the mean of its divisors is an integer number (25716725112).
Almost surely, 251433450223 is an apocalyptic number.
51433450223 is a deficient number, since it is larger than the sum of its proper divisors (1).
51433450223 is an equidigital number, since it uses as much as digits as its factorization.
51433450223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 43200, while the sum is 32.
Adding to 51433450223 its reverse (32205433415), we get a palindrome (83638883638).
The spelling of 51433450223 in words is "fifty-one billion, four hundred thirty-three million, four hundred fifty thousand, two hundred twenty-three".
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