Base | Representation |
---|---|
bin | 100101011011000101101… |
… | …1100010100111101001000 |
3 | 200012201001110022211201211 |
4 | 1022312023130110331020 |
5 | 1133232203304442300 |
6 | 14534504040222504 |
7 | 1040412424541644 |
oct | 112661334247510 |
9 | 20181043284654 |
10 | 5143415312200 |
11 | 1703345945270 |
12 | 6b09b346aa34 |
13 | 2b40393b0849 |
14 | 13ad2a809c24 |
15 | 8dbd31c24ba |
hex | 4ad8b714f48 |
5143415312200 has 96 divisors (see below), whose sum is σ = 13048325746560. Its totient is φ = 1869937977600.
The previous prime is 5143415312177. The next prime is 5143415312239. The reversal of 5143415312200 is 22135143415.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 10278202 + ... + 10766998.
It is an arithmetic number, because the mean of its divisors is an integer number (135920059860).
Almost surely, 25143415312200 is an apocalyptic number.
5143415312200 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 5143415312200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (6524162873280).
5143415312200 is an abundant number, since it is smaller than the sum of its proper divisors (7904910434360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5143415312200 is a wasteful number, since it uses less digits than its factorization.
5143415312200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 493607 (or 493598 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 31.
The spelling of 5143415312200 in words is "five trillion, one hundred forty-three billion, four hundred fifteen million, three hundred twelve thousand, two hundred".
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