Base | Representation |
---|---|
bin | 100101011011010111010… |
… | …0111010101110000011111 |
3 | 200012202120120200111020221 |
4 | 1022312232213111300133 |
5 | 1133234410340323011 |
6 | 14535042400022211 |
7 | 1040433151323205 |
oct | 112665647256037 |
9 | 20182516614227 |
10 | 5144005401631 |
11 | 1703618a44188 |
12 | 6b0b39001967 |
13 | 2b41017194a5 |
14 | 13ad84d33075 |
15 | 8dc19dd3971 |
hex | 4adae9d5c1f |
5144005401631 has 2 divisors, whose sum is σ = 5144005401632. Its totient is φ = 5144005401630.
The previous prime is 5144005401553. The next prime is 5144005401637. The reversal of 5144005401631 is 1361045004415.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5144005401631 - 219 = 5144004877343 is a prime.
It is a super-3 number, since 3×51440054016313 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5144005401637) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2572002700815 + 2572002700816.
It is an arithmetic number, because the mean of its divisors is an integer number (2572002700816).
Almost surely, 25144005401631 is an apocalyptic number.
5144005401631 is a deficient number, since it is larger than the sum of its proper divisors (1).
5144005401631 is an equidigital number, since it uses as much as digits as its factorization.
5144005401631 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 28800, while the sum is 34.
The spelling of 5144005401631 in words is "five trillion, one hundred forty-four billion, five million, four hundred one thousand, six hundred thirty-one".
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