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514410000037 is a prime number
BaseRepresentation
bin1110111110001010011…
…10011010111010100101
31211011210010011120010121
413133011032122322211
531412002430000122
61032152223321541
752110362566303
oct7370516327245
91734703146117
10514410000037
1118918404183a
1283842a502b1
133967c68cb0b
141ac7cd45273
15d5aac52bc7
hex77c539aea5

514410000037 has 2 divisors, whose sum is σ = 514410000038. Its totient is φ = 514410000036.

The previous prime is 514409999989. The next prime is 514410000043. The reversal of 514410000037 is 730000014415.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 266471731681 + 247938268356 = 516209^2 + 497934^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-514410000037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 514409999966 and 514410000020.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (514410000737) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 257205000018 + 257205000019.

It is an arithmetic number, because the mean of its divisors is an integer number (257205000019).

Almost surely, 2514410000037 is an apocalyptic number.

It is an amenable number.

514410000037 is a deficient number, since it is larger than the sum of its proper divisors (1).

514410000037 is an equidigital number, since it uses as much as digits as its factorization.

514410000037 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1680, while the sum is 25.

The spelling of 514410000037 in words is "five hundred fourteen billion, four hundred ten million, thirty-seven", and thus it is an aban number.