Base | Representation |
---|---|
bin | 10111011001011011101101… |
… | …10011000010110001111111 |
3 | 20202011201001222020020201011 |
4 | 23230231312303002301333 |
5 | 23220434440010043012 |
6 | 301232241052100051 |
7 | 13560145545605254 |
oct | 1354556663026177 |
9 | 222151058206634 |
10 | 51451406331007 |
11 | 154374675a1761 |
12 | 592b763a64627 |
13 | 2292b01553b97 |
14 | c9c39322342b |
15 | 5e3580d5a1a7 |
hex | 2ecb76cc2c7f |
51451406331007 has 2 divisors, whose sum is σ = 51451406331008. Its totient is φ = 51451406331006.
The previous prime is 51451406330999. The next prime is 51451406331029. The reversal of 51451406331007 is 70013360415415.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51451406331007 - 23 = 51451406330999 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51451406331107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25725703165503 + 25725703165504.
It is an arithmetic number, because the mean of its divisors is an integer number (25725703165504).
Almost surely, 251451406331007 is an apocalyptic number.
51451406331007 is a deficient number, since it is larger than the sum of its proper divisors (1).
51451406331007 is an equidigital number, since it uses as much as digits as its factorization.
51451406331007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 151200, while the sum is 40.
The spelling of 51451406331007 in words is "fifty-one trillion, four hundred fifty-one billion, four hundred six million, three hundred thirty-one thousand, seven".
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