Base | Representation |
---|---|
bin | 1001100101100101… |
… | …10010111000110101 |
3 | 111021201020222211002 |
4 | 10302302302320311 |
5 | 41020132044413 |
6 | 2210425053045 |
7 | 241356666644 |
oct | 46262627065 |
9 | 14251228732 |
10 | 5147143733 |
11 | 22014792a6 |
12 | bb7927185 |
13 | 64049a6a4 |
14 | 36b84535b |
15 | 201d1e958 |
hex | 132cb2e35 |
5147143733 has 2 divisors, whose sum is σ = 5147143734. Its totient is φ = 5147143732.
The previous prime is 5147143717. The next prime is 5147143751. The reversal of 5147143733 is 3373417415.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 4959398929 + 187744804 = 70423^2 + 13702^2 .
It is a cyclic number.
It is not a de Polignac number, because 5147143733 - 24 = 5147143717 is a prime.
It is a super-2 number, since 2×51471437332 = 52986177216322350578, which contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5147143783) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2573571866 + 2573571867.
It is an arithmetic number, because the mean of its divisors is an integer number (2573571867).
Almost surely, 25147143733 is an apocalyptic number.
It is an amenable number.
5147143733 is a deficient number, since it is larger than the sum of its proper divisors (1).
5147143733 is an equidigital number, since it uses as much as digits as its factorization.
5147143733 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 105840, while the sum is 38.
The square root of 5147143733 is about 71743.5971568195. The cubic root of 5147143733 is about 1726.5881874550.
The spelling of 5147143733 in words is "five billion, one hundred forty-seven million, one hundred forty-three thousand, seven hundred thirty-three".
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