Base | Representation |
---|---|
bin | 1100010001110… |
… | …0100010110111 |
3 | 10120220022210121 |
4 | 3010130202313 |
5 | 101140402033 |
6 | 5035432411 |
7 | 1163501305 |
oct | 304344267 |
9 | 116808717 |
10 | 51497143 |
11 | 27083625 |
12 | 152b5707 |
13 | a8909a9 |
14 | 6ba7275 |
15 | 47c362d |
hex | 311c8b7 |
51497143 has 2 divisors, whose sum is σ = 51497144. Its totient is φ = 51497142.
The previous prime is 51497129. The next prime is 51497153. The reversal of 51497143 is 34179415.
51497143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51497143 is a prime.
It is equal to p3085459 and since 51497143 and 3085459 have the same sum of digits, it is a Honaker prime.
It is a junction number, because it is equal to n+sod(n) for n = 51497099 and 51497108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51497113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25748571 + 25748572.
It is an arithmetic number, because the mean of its divisors is an integer number (25748572).
Almost surely, 251497143 is an apocalyptic number.
51497143 is a deficient number, since it is larger than the sum of its proper divisors (1).
51497143 is an equidigital number, since it uses as much as digits as its factorization.
51497143 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 15120, while the sum is 34.
The square root of 51497143 is about 7176.1509878207. The cubic root of 51497143 is about 372.0440629773.
The spelling of 51497143 in words is "fifty-one million, four hundred ninety-seven thousand, one hundred forty-three".
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