Base | Representation |
---|---|
bin | 100101011110010100011… |
… | …1011001111001001001111 |
3 | 200020100221220200200011102 |
4 | 1022330220323033021033 |
5 | 1133340410203430241 |
6 | 14542012250213315 |
7 | 1041046351055336 |
oct | 112745073171117 |
9 | 20210856620142 |
10 | 5150352405071 |
11 | 1706285732875 |
12 | 6b220a72423b |
13 | 2b48a365c523 |
14 | 13b3c7c6cd1d |
15 | 8de8c21239b |
hex | 4af28ecf24f |
5150352405071 has 2 divisors, whose sum is σ = 5150352405072. Its totient is φ = 5150352405070.
The previous prime is 5150352405031. The next prime is 5150352405131. The reversal of 5150352405071 is 1705042530515.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5150352405071 - 218 = 5150352142927 is a prime.
It is a super-2 number, since 2×51503524050712 (a number of 26 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5150352405001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2575176202535 + 2575176202536.
It is an arithmetic number, because the mean of its divisors is an integer number (2575176202536).
Almost surely, 25150352405071 is an apocalyptic number.
5150352405071 is a deficient number, since it is larger than the sum of its proper divisors (1).
5150352405071 is an equidigital number, since it uses as much as digits as its factorization.
5150352405071 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 105000, while the sum is 38.
Adding to 5150352405071 its reverse (1705042530515), we get a palindrome (6855394935586).
The spelling of 5150352405071 in words is "five trillion, one hundred fifty billion, three hundred fifty-two million, four hundred five thousand, seventy-one".
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