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5158675212413 is a prime number
BaseRepresentation
bin100101100010001100100…
…0000001110100001111101
3200021011102221112002111012
41023010121000032201331
51134004431323244123
614545510201005005
71041462531545642
oct113043100164175
920234387462435
105158675212413
111709866742148
126b3951a83765
132b55cba275b8
1413b977365dc9
158e2c7c24378
hex4b11900e87d

5158675212413 has 2 divisors, whose sum is σ = 5158675212414. Its totient is φ = 5158675212412.

The previous prime is 5158675212403. The next prime is 5158675212463. The reversal of 5158675212413 is 3142125768515.

It is an a-pointer prime, because the next prime (5158675212463) can be obtained adding 5158675212413 to its sum of digits (50).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4880374650649 + 278300561764 = 2209157^2 + 527542^2 .

It is a cyclic number.

It is not a de Polignac number, because 5158675212413 - 212 = 5158675208317 is a prime.

It is a super-2 number, since 2×51586752124132 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (5158675212403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2579337606206 + 2579337606207.

It is an arithmetic number, because the mean of its divisors is an integer number (2579337606207).

Almost surely, 25158675212413 is an apocalyptic number.

It is an amenable number.

5158675212413 is a deficient number, since it is larger than the sum of its proper divisors (1).

5158675212413 is an equidigital number, since it uses as much as digits as its factorization.

5158675212413 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2016000, while the sum is 50.

The spelling of 5158675212413 in words is "five trillion, one hundred fifty-eight billion, six hundred seventy-five million, two hundred twelve thousand, four hundred thirteen".