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51642713480231 is a prime number
BaseRepresentation
bin10111011111000000000011…
…00101111001110000100111
320202211222212111101100201102
423233200001211321300213
523232103234122331411
6301500200212150315
713610030403545066
oct1357400145716047
9222758774340642
1051642713480231
1115500608489465
12596085430839b
1322a7b6b924973
14ca7740a041dd
155e852b074d3b
hex2ef801979c27

51642713480231 has 2 divisors, whose sum is σ = 51642713480232. Its totient is φ = 51642713480230.

The previous prime is 51642713480147. The next prime is 51642713480249. The reversal of 51642713480231 is 13208431724615.

51642713480231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51642713480231 is a prime.

It is a super-2 number, since 2×516427134802312 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51642713480251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25821356740115 + 25821356740116.

It is an arithmetic number, because the mean of its divisors is an integer number (25821356740116).

Almost surely, 251642713480231 is an apocalyptic number.

51642713480231 is a deficient number, since it is larger than the sum of its proper divisors (1).

51642713480231 is an equidigital number, since it uses as much as digits as its factorization.

51642713480231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 967680, while the sum is 47.

The spelling of 51642713480231 in words is "fifty-one trillion, six hundred forty-two billion, seven hundred thirteen million, four hundred eighty thousand, two hundred thirty-one".