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516492877013 is a prime number
BaseRepresentation
bin1111000010000010101…
…11111101110011010101
31211101011021110200012022
413201001113331303111
531430234134031023
61033135030502525
752213114006031
oct7410127756325
91741137420168
10516492877013
1118a052845073
1284124504a45
1339922063bb9
141add98151c1
15d67da367c8
hex78415fdcd5

516492877013 has 2 divisors, whose sum is σ = 516492877014. Its totient is φ = 516492877012.

The previous prime is 516492877009. The next prime is 516492877079. The reversal of 516492877013 is 310778294615.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 512852202769 + 3640674244 = 716137^2 + 60338^2 .

It is a cyclic number.

It is not a de Polignac number, because 516492877013 - 22 = 516492877009 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (516492877513) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258246438506 + 258246438507.

It is an arithmetic number, because the mean of its divisors is an integer number (258246438507).

It is a 2-persistent number, because it is pandigital, and so is 2⋅516492877013 = 1032985754026, but 3⋅516492877013 = 1549478631039 is not.

Almost surely, 2516492877013 is an apocalyptic number.

It is an amenable number.

516492877013 is a deficient number, since it is larger than the sum of its proper divisors (1).

516492877013 is an equidigital number, since it uses as much as digits as its factorization.

516492877013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2540160, while the sum is 53.

The spelling of 516492877013 in words is "five hundred sixteen billion, four hundred ninety-two million, eight hundred seventy-seven thousand, thirteen".