Base | Representation |
---|---|
bin | 1111000010011001111… |
… | …10000110110111100001 |
3 | 1211101122211112201212001 |
4 | 13201030332012313201 |
5 | 31431133440044433 |
6 | 1033210220404001 |
7 | 52220665435225 |
oct | 7411476066741 |
9 | 1741584481761 |
10 | 516687424993 |
11 | 18a142643923 |
12 | 841796a6601 |
13 | 3995345c74c |
14 | 1b0175b8785 |
15 | d690b6557d |
hex | 784cf86de1 |
516687424993 has 2 divisors, whose sum is σ = 516687424994. Its totient is φ = 516687424992.
The previous prime is 516687424991. The next prime is 516687425081. The reversal of 516687424993 is 399424786615.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 395619614289 + 121067810704 = 628983^2 + 347948^2 .
It is a cyclic number.
It is not a de Polignac number, because 516687424993 - 21 = 516687424991 is a prime.
Together with 516687424991, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (516687424991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258343712496 + 258343712497.
It is an arithmetic number, because the mean of its divisors is an integer number (258343712497).
Almost surely, 2516687424993 is an apocalyptic number.
It is an amenable number.
516687424993 is a deficient number, since it is larger than the sum of its proper divisors (1).
516687424993 is an equidigital number, since it uses as much as digits as its factorization.
516687424993 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 78382080, while the sum is 64.
The spelling of 516687424993 in words is "five hundred sixteen billion, six hundred eighty-seven million, four hundred twenty-four thousand, nine hundred ninety-three".
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