Base | Representation |
---|---|
bin | 110000001011110111… |
… | …101001100100101001 |
3 | 11221112202120120112121 |
4 | 300023313221210221 |
5 | 1321430104321004 |
6 | 35433552511241 |
7 | 3511064035351 |
oct | 601367514451 |
9 | 157482516477 |
10 | 51738745129 |
11 | 1aa40199aa5 |
12 | a03b24b521 |
13 | 4b570638b6 |
14 | 270b61db61 |
15 | 152c34d854 |
hex | c0bde9929 |
51738745129 has 2 divisors, whose sum is σ = 51738745130. Its totient is φ = 51738745128.
The previous prime is 51738745127. The next prime is 51738745141. The reversal of 51738745129 is 92154783715.
51738745129 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 40640544025 + 11098201104 = 201595^2 + 105348^2 .
It is a cyclic number.
It is not a de Polignac number, because 51738745129 - 21 = 51738745127 is a prime.
Together with 51738745127, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (51738745127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25869372564 + 25869372565.
It is an arithmetic number, because the mean of its divisors is an integer number (25869372565).
Almost surely, 251738745129 is an apocalyptic number.
It is an amenable number.
51738745129 is a deficient number, since it is larger than the sum of its proper divisors (1).
51738745129 is an equidigital number, since it uses as much as digits as its factorization.
51738745129 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2116800, while the sum is 52.
The spelling of 51738745129 in words is "fifty-one billion, seven hundred thirty-eight million, seven hundred forty-five thousand, one hundred twenty-nine".
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