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51738745141 is a prime number
BaseRepresentation
bin110000001011110111…
…101001100100110101
311221112202120120120001
4300023313221210311
51321430104321031
635433552511301
73511064035366
oct601367514465
9157482516501
1051738745141
111aa4019a006
12a03b24b531
134b570638c5
14270b61db6d
15152c34d861
hexc0bde9935

51738745141 has 2 divisors, whose sum is σ = 51738745142. Its totient is φ = 51738745140.

The previous prime is 51738745129. The next prime is 51738745147. The reversal of 51738745141 is 14154783715.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 51224816241 + 513928900 = 226329^2 + 22670^2 .

It is a cyclic number.

It is not a de Polignac number, because 51738745141 - 211 = 51738743093 is a prime.

It is a super-2 number, since 2×517387451412 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 51738745091 and 51738745100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51738745147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25869372570 + 25869372571.

It is an arithmetic number, because the mean of its divisors is an integer number (25869372571).

Almost surely, 251738745141 is an apocalyptic number.

It is an amenable number.

51738745141 is a deficient number, since it is larger than the sum of its proper divisors (1).

51738745141 is an equidigital number, since it uses as much as digits as its factorization.

51738745141 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 470400, while the sum is 46.

The spelling of 51738745141 in words is "fifty-one billion, seven hundred thirty-eight million, seven hundred forty-five thousand, one hundred forty-one".