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51783411983 is a prime number
BaseRepresentation
bin110000001110100010…
…000010100100001111
311221122212121212221112
4300032202002210033
51322023023140413
635442230122235
73512145511412
oct601642024417
9157585555845
1051783411983
111aa63427956
12a0521b037b
134b633a26a4
142713529b79
1515312232a8
hexc0e88290f

51783411983 has 2 divisors, whose sum is σ = 51783411984. Its totient is φ = 51783411982.

The previous prime is 51783411943. The next prime is 51783412007. The reversal of 51783411983 is 38911438715.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-51783411983 is a prime.

It is a super-2 number, since 2×517834119832 (a number of 22 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (51783411913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25891705991 + 25891705992.

It is an arithmetic number, because the mean of its divisors is an integer number (25891705992).

Almost surely, 251783411983 is an apocalyptic number.

51783411983 is a deficient number, since it is larger than the sum of its proper divisors (1).

51783411983 is an equidigital number, since it uses as much as digits as its factorization.

51783411983 is an evil number, because the sum of its binary digits is even.

The product of its digits is 725760, while the sum is 50.

The spelling of 51783411983 in words is "fifty-one billion, seven hundred eighty-three million, four hundred eleven thousand, nine hundred eighty-three".